Question

Forces and Newton's LAWS WU PHYS 1107 - General Physics I ) An 9.0 kg mass (M) is placed on a horizontal surface. A massless rope runs over a frictionless massless pulley which connects the mass M to a 6.5 kg mass (m) that hangs vertically. a) What is the acceleration of the vertical mass if the horizontal surface is frictionless? b) What is the tension in the rope if the horizontal surface is frictionless? Now assume that the horizontal surface has a co-efficient of static friction of 0.25 and a co-efficient of kinetic friction of 0.15. c) What is the new acceleration of the vertical mass? d) What is the smallest mass that the that the hanging vertical mass (m) could have and still have a non-zero acceleration? Hint: For the blocks to move, the tension force must be able to overcome the static friction force acting on the block with mass M.

Answer 1

5 P 4 +Enter Pa Dn M9-T6 m,a TEM2A mi 19-m2a 6.5 9.8 az 6-5+9 4.11 0162 Tem2a5 94.11 2 7 N again T-S Mm2 Frickion M adding ond on 6.5x9.8-O.15x9 x 9.8 C6.5+9) 9t 3.26 /s Sus& begining of accelension Fon Te 0.25x9x9.8 22.05 N ,22.05 2.25 ke 9.8 t V

F cose-mg sine-mo N- FSin9-m8 CoOMO Fsing + Mgcose Nanmal fanae N=

10 T. 1 2 60x9.2 588 N TeD T, T2 con37 T CosYE T2 0.885 T3 also T2 sin3+ T3Sin 5=T 1 O.885 5in32 Ta Ta sin45 + 474.3 N Te 1 O.885x 4F-3 T2 T2 419.76 N
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