we can use the conservation of energy to solve this problem,
The sum of Kinetic energy =Sum of the potential energy
i.e
(1/2)mvi2+(1/2)mvf2=mgh
Once it reaches ground the final height =0 or the final potential energy=0
vi=inital velocity
vf=Final velocity
(1/2)m62+(1/2)m132=mgh
m is common in both sides, so let us cancel in both sides
So,1/2(36+169)=gh
102.5=gh
h=10.459 m
Height of the hill is 10.46 m
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