Homework Answers
The reactions are
PbCo3+2HNO3---------> Pb(NO3)2 + H2O(l) +CO2(g)
Pb(NO3)2 + 2HCl ------>PBCl2 +2HNO3
when added, the reactions
Pb(CO3)+ 2HCL-------> PbCl2 + H2O(l) +CO2(g)
Molar mas of Pb(CO3) =267 and that of PbCl2= 278
moles: Pb(CO3)2= 4/267=0.015
from the final reaction, moles of PbCl2 formed from 1 mole of Pb(CO3)2, the limiting reactant are =0.015
Mass of PbCl2 formed = moles* Molar mass =0.015*278= 4.17 gm. This is the theoretical yield
% yield = 100*(actual yield/theoretical yield)=100*3.571/4.17=85.64%
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