Question

Kindly solve them all or dont even attempt wasting my question. thankyou

1 1 For the sequence anan-1-an-2+ an-3, ao = 1, a1 = 1, and a2 = 2, the values of the first six terms are ao = 10.02- 2 .23 - 4 .24- 7 , and a5- 13

Answer 1

1) anap-1-an-z tan-z e ao=1 a, 1 92=2 - Substitute 0-3, i Az = az-a, tas 2-1 + 1 = 2 Substituting n=4, a4=Qz-az ta, - 2-2 + 1 - 1 Iely ag=a4-azt az 1-2 +2 = 1 20=1, 0,-1, 2, = 2 , 03 = 2 , 9451,95: 1 2.) ap: manast (an-a) 2 do - a, =0 aa = 2a, +(ao)² Az = 594 +az -2(0)+(-))?= 1 - 5x13 +9 az=39+ (a.)² = 74 -3.1+0 -3 a=747 au= q az + (aq)² Qy = 13 @,507 :34.3 + 1 - 13 a = 37 doe-T)

10++ +84 +224) Ž (361 :: 36 } ->) - 30/0+ 1+ 2+) = 30x5 180 = 180 M. mW: - 3+3+3=9 = Ans M M "W: 33:42· 3 (s40) + 158 +2)t (30+4) - Ž ( 91 +6) = (9.0+ 9.1 +9.2+9.3) +611+1+1+1) - 9+18+27 + 24 = 78 = Ans

Wo IMN (i-j). (10-1) + (8-)) Y = (2,1+2.2 +2.3) - 3 (1+1+1) 12-9 - 3 - Ans or equal ana Ln/2] In/2) is floor function. ve greatest integer less than to) n/2 Ag - Lod - 0 a, = 1/2] = 10.5) - 0 Az = [2/2] - 1 9 az z L3/2] : 11.53 - 1 lao=0 g 9,=0 g ag=1993=1

Answer 2

Port (t) [no=1] ; an-an-iran-atang - a =1 g -1+1=2 a4=2-2 +1=1 as= 1-2+2= a=2-1+2=2 Part 18 ana nanay tan-a Qo=-1 a, = 2a, + ax = axo + = 1 az= 3 4g + a2 = 3 au = 49z+aze = 12+1=13 as = say tay = 65+9 = 74

Part = itric +27 il = (0+1+4) +8(0+1+y) +27(0+1+4) = (1+ +37)x5 = 180 Pareted) MWA Ž j - Ž (otite) = 3 +3+3 Part le). +(3i+4) 9 1 +6 = = = (0+5]+9+6)+(18+5)+(2776) 6 + 15 + 24 +33 78

Past (f) 2 (0 - ) = (4-1) + (-2) - festo Ž 2-3 = -1 +1+3 Part (9) an= lnial function ALA i It is Grest Integer functim It is also called by one another dume (floor It is bilver Just Lessor integer. An noap Lal=0 a,= L 'al=0 az ( 212 ) = 1 az= L 3/2) = (15)=1