Question

/*

   Write a function that takes as an argument the value x,

   and returns the result of the expression: 20x^4 - 12x^3 - 3x^2 + 15x + 3

   Note: No importing; use the power function given to you, and use it

   as a reference for writing functions (note also that main itself

       if a function!).

*/

public class Exercise9_1

{

public static void main(String[] args)

{

int num = 5, pow = 2;

System.out.println(num + "^" + pow + " == " + power(num,pow));

}

  

// power function: Calculate x^n, return result

public static double power(double x, int n)

{

double product = 1;

      

// If to the power of 0, just simply return 1

if(n == 0)

return product;

      

// Otherwise calculate the product and return the result

for(int i = 0; i < n; i++)

product *= x;

      

return product;

}

}

Answer 1

import java.util.Scanner;

public class Exercise9_1 {
  
   public static void main(String[] args)
   {
   int num , pow = 2;
   System.out.println("Enter the value of x: ");
   Scanner sc = new Scanner(System.in);
   num = sc.nextInt();
   //System.out.println(num + "^" + pow + " == " + power(num,pow));
   System.out.println("\nExpresion 20x^4 - 12x^3 - 3x^2 + 15x + 3, For x= " + num + " is " + cal_expression(num,pow));
     
   }
  
   public static double cal_expression(double x, int n)
   {
       double value=(20*power(x,4))-(12*power(x,3))-(3*power(x,2))+(15*power(x,1))+3;
       return value;
   }
   // power function: Calculate x^n, return result
   public static double power(double x, int n)
   {
   double product = 1;
  
   // If to the power of 0, just simply return 1
   if(n == 0)
   return product;
  
   // Otherwise calculate the product and return the result
   for(int i = 0; i < n; i++)
   product *= x;
   return product;
   }

}

Code Image:

3 import java.util.Scanner; 4 5 public class numbers 6 public static void main (String args) 8 9 10 int num , pow 2; System.out.println( "Enter the value of x: "); Scanner sc new Scanner (System.in); numsc.nextInt(); //System.out.println(num+pow+"+power (num, pow)) System.out.println("\nExpresion 20x 412x 3 - 3x*2 15x 3, For x" + num " is " + cal_expression (num, pow)) 12 13 14 15 16 17 18 19e 20 21 public static double cal_expression (double x, int n) double value- (20*power(x,4)) (12*power(x,3))-(3*power(x,2))+(15*power(x,1))+3; return value; 23 24 25e 26 27 28 29 30 31 32 // power function: Calculate x*n, return result public static double power (double x, int n) double product = 1; // If to the power of θ, just simply return 1 if(n == θ) return product; // Otherwise calculate the product and return the result for(int i = 0; i< n; i++) 34 35 36 37 38 product *-X; return product;

Output Image:

<terminated» numbers [Java Application] /usr/lib/jvm/java-8-openjdk-amd64/bin/java (19-Dec-2016, 2:48:17 PM) Enter the value of x: Expresion 26x24-12x^3-3x^2 + 15x + 3, For x- 5 ǐs 110θ3.θ