Question

Torce is saw horse A exerting on uie pralk! 181V 14. K 4.0 m - A 4.0 m long fir plank weighs 320 N. It is resting on two saw horses, as shown. If x = 20.0 cm and y = 80.0 cm, what is the downward force being exerted by the plank (a) on saw horse A? 128 (b) on saw horse B? 142 N 15. A 4.0 m long fir plank weighs 320 N. It is resting on two saw horses, as shown. #06mk 2.8 in *0.6mk (a) What is the heaviest weight that can rest on end "y" without causing the plank to flip upward? (b) If a 1500 N football lineman is to sit on end "y" without causing the plank to flip upward, what is the maximum distance from end "y" that saw horse B can be located? 35 m

Both questions steps, two questions are similar, but i don’t know how to set pivot and make formula. Please help me thx?

Answer 1

JU um: : 08m Balancing forces Rat R8 = 320N -☺ Balancing moment about A, Rgx (3-8-0-8) - 320 x 1.8 = 0 R8 = 1921 RA - 320 - RB - 320-192 RA = 1 3 8 N a> Force on saw horse A = 128N. b> Force on. Saw horse B = 1925

is) t ym AVTB 1320N RARB Form Forca as heaviest weight be F. For heat tip over, RAFO in moment about 'B=. 320 x 46-06) - Fx0.6 Fe 320x104 - 746.66 N ~ 747N 0.6 - b) For no-flip in Lety = aC. For equilibrium 320x(-x) = 1500 (8) 640-32006= 15000 a = but do OC - 0.3516 m * = 0.35 m