Unfortunately, I do not have Visual Studio but I will provide you with a working c++ code that you can run either in Linux or any windows IDE. Also please forgive me but I have not used the sample code given by you to stop the execution time for some seconds if the selected cards do not match. I will post some screenshots of my console output and I think the game works in the same way and the output is also produced in the same manner as suggested in the question. I have not deviated from it. My code will contain all the required and important documentation so any explanation over here I think would not be much necessary. Here goes the code (with necessary documentation) and the output screenshots after that.
#include <bits/stdc++.h> // imports all the necessary header files
#define ll long long int // all data types are in 64bit just for being in the safe side.
using namespace std;
vector <char> v;
int main()
{
/*
here i am storing all the
characters from A to H in a vector twice because
you need two of them and then i
shuffled them randomly and also created a
puzzle matrix and a visited matrix.
The puzzle matrix stores the randomly
shuffed vector of characters and
visited marks the set of cards that are already
the same and the player has
selected. That is vis[i1][j1] = true and vis[i2][j2] = true
denotes that the player has found
out that the cards at (i1, j1) and (i2, j2) are the
same.
*/
for(char ch = 'A'; ch <= 'H'; ch++)
{
v.push_back(ch);
v.push_back(ch);
}
srand(time(0));
random_shuffle(v.begin(), v.end());
ll sz = v.size();
char puzzle[4][4];
ll vis[4][4];
for(ll i = 0; i < 4; i++)
for(ll j = 0; j < 4; j++)
vis[i][j] =
false;
ll r = -1, c = 0;
// here i am transferring the values from the vector v
to the puzzle matrix.
for(ll i = 0; i < sz; i++)
{
if(i % 4 == 0)
{
r++;
c = 0;
}
puzzle[r][c] = v[i];
c++;
}
// game starts from here
for(ll i = 0; i < 4; i++)
{
for(ll j = 0; j < 4; j++)
cout <<
"X";
cout << endl;
}
ll moves = 0;
while(1)
{
cout << "Choose two cards (or
'q' to quit the game):";
string inp;
getline(cin, inp); // space
separeted input is taken in the form a b c d.
if(inp == "q") // if only "q"
appears quit the game.
{
cout <<
"you have quitted the game" << endl;
break;
}
moves++;
ll x1 = inp[0] - '0'; // zeroth
element is the first row
ll y1 = inp[2] - '0'; // second
element is the first column
ll x2 = inp[4] - '0'; // fourth
element is the second row
ll y2 = inp[6] - '0'; // sixth
element is the second column
// 0 2 4 6 because it matches the
input like (a_b_c_d) -> (0123456)
if(puzzle[x1][y1] ==
puzzle[x2][y2]) // if the selected coordinates has the same
cards
{
vis[x1][y1] =
true;
vis[x2][y2] =
true; // mark them as true
for(ll i = 0; i
< 4; i++)
{
for(ll j = 0; j < 4; j++)
{
if(vis[i][j])
cout
<< puzzle[i][j]; // if it is visited means the player has
already discovered it
else
cout
<< "X"; // else it is undiscovered still.
}
cout << endl;
// And print it!!
}
}
else
{
// if the
coordinates does not match
for(ll i = 0; i
< 4; i++)
{
for(ll j = 0; j < 4; j++)
{
if(vis[i][j] || (i == x1
&& j == y1) || (i == x2 && j == y2))
cout
<< puzzle[i][j]; // we see if it has been discovered or is
the current index
else
cout
<< "X"; // else undiscovered
}
cout << " ";
}
cout <<
endl;
for(ll i = 0; i
< 4; i++)
{
for(ll j = 0; j < 4; j++)
{
if(vis[i][j])
cout
<< puzzle[i][j];
else
cout
<< "X";
}
cout << endl;
}
// Just Normal
printing after a round of the game.
}
bool ok = true;
for(ll i = 0; i < 4; i++)
for(ll j = 0; j
< 4; j++)
if(vis[i][j] == false)
ok = false;
// Now if the entire vis matrix has
been marked true means the player
// has discovered all the cards and
he has won the game and we exit the game.
if(ok)
{
cout <<
"Congratulations! You solved the puzzle in " << moves
<< " moves.";
break;
}
}
return 0;
}

I hope I explained the code clearly and the output is in the form suitable towards you. However if any kind of doubt still arises from your side regarding the code or the output, just leave a comment down below and I will be more than happy to help you out any time. Just ask me and I am there to help. If you think I did justice to your question give it a thumbs up. It means a lot. Thank you.
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