Question

1. Calculate the average value of the electric field along the straight line between the two parallel line charges by dividing the difference in the magnitude of the voltages at the two parallel lines by the displacement between them. Then take the % difference between your two values for the average electric field between the parallel line charges. (10 points)

Two Parallel Line Charge Configuration
Vi (V)	Xi (m)	E (V/m)
114.5	0.5
63.1	1	102.8
36.4	1.5	53.4
16.6	2	39.6
0.22	2.5	32.76
-16.1	3	32.64
-35.4	3.5	38.6
-64.1	4	57.4
-114.1	4.5	100
		Eavg(V/m)
		57.15

Answer 1

Two Parallel line Charge Configuration V:CV) Xicm) E (VI) 114.5 0.5 63.1 1 36.4 1.5 2 16.6 2.5 0.22 3 -16.1 3.5 35.4 - 64.1 4 - - 11401 4,5 Calculating E (um) values E, 114.5 -63.1. 102.8 0.5 E 63.1 - 36.4 = 26.7 1 E, 36.4 - 16.6 13.2 1.5 Ea 16.6 0.22 8.19 2

Es 1) 0.22-(-16) = 6.528 2.5 Е, 11 -16.1-(-35.4) 6.433 3 Ez 7 Il - 35.4 -(-6) 8.2 3.5 Eg - 64.1 (-114.) = 12.5 4 Eaug (Vm) = E + Ez t Et En test Est Est Ep = 8 102.8 t 26.7 +13,2 + 8.19 + 6.528 t 6.433 + 8.2 +12.5 s 23.069

Calcul culating percentage difference Given Eaug (uim) value in difference Question is .. 57:15 Percentage in E values 1 Ecalialaled - Eninen * 100 E Giren = 123,069 - 57:15 *loo 57.15 = 59.631