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A reaction that occurs in the internal combustion


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Answer #1

a) DH0= DH0products-DH0reagents= 2 x 90.25KJ/mol -(0 + 0)= 180.5KJ

DS0=S0products-S0reagents= 2 x 210.76J/molK-(191.61J/molk + 205.14J/molK)= 24.77J/K

b) DG0=DH0 -TDS0 = 180.5KJ - 342Kx0.02477KJ/K= 172.03KJ (At 69

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