Question

1. Find the average rate of change of g(t) = +1 from t=2 to t=5. Answer: 2. Find the difference quotient and derivative (using the definition) for f(x) = 2/3. f(a+h) - (0) Jun (18+) Me

Answer 1

git)= 114 (1) Given that from t-g to th t-1 The average rate of change of f(t) on the interval [a,b] is $12)-a) we have a=2, 625 Thus, g(b)- gaj (5th) - (274) 6-a 6-a 5-2 a 4 9.24 12 12 6) =-54 Average rate of change is = 3 -5 as --125 (2) Given that f = 250 of (ath)-fa) 27th - 20h h Rationalize with ar h 2rathtara (2.1976)-(28432 (::Sa+b)/2-6)=2²-62) nathu ) = 4(x+h)-47, h 26th+280) • 4x+4h-gx h(27th+284)

4h (2/4th+282) flath)-f(0) 4 24th tara h 4 lim feath)-f(x) lim h=0 = ho akathtava h 4 4 Zato + Wu 48x The lim f(ath)-f(?) hoo h.