Question

What are the coefficients for the following reaction when it is properly balanced? __ Na3PO4 + __ Ba(NO2)2 --> __NaNO2 + __Bag(PO4)2 1, 2, 2, 1 2,1,1, 3 2,3,6,1 2,3,1,6 6,1,2,3

Answer 1

The answer is C :2,3,6,1

Explanation

Balance equation will be

2Na3PO4 + 3 Ba(NO2)2 ---> 6NaNO2 + 1Ba3(PO4)2

Here all the constituent of reactant side must be equal to the product side

In this type of question you should go for hit and trail method of available option given it is effective and time consuming details solution is given below

DETAILS PROCEDURE :

Na3PO4 + Ba(NO2)2 ---> NaNO2 + Ba3(PO4)2

first balance the PO4 3- by multiplying 2 on reactant side so both side PO4 3- will be same

2Na3PO4 + Ba(NO2)2 ---> NaNO2 + Ba3(PO4)2

now balance the Na atom by multiplying 6 in the product side so the Na will be 6 in both side

2Na3PO4 + Ba(NO2)2 ---> 6NaNO2 + Ba3(PO4)2

now balance Ba and NO2 - by multiplying 3 in the reactant side

2Na3PO4 + 3 Ba(NO2)2 ---> 6NaNO2 + 1Ba3(PO4)2

now it is balanced and the coefficient is 2,3,6,1

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