Question

Solve the equation in degrees for all exact solutions where appropriate. Round approximate answers 5 sin 0 = 5 cos 20 What is the solution set? O A. {30°, + 360°n, 120° + 360°n, 270° + 360°n, where n is any integer; OB. {0° + 180°n, 120° +180°n, 240° + 180°n, where n is any integer; O C. (30° + 360°n, 150° + 360°n, 270° + 360°n, where n is any integer} OD. {0° + 360°n, 150° + 360°n, 240° + 360ºn, where n is any iteger)

Answer 1

(cos 20 = 1-2 sido ) 5 sin d = 5 COS 208 sino cos 20 7 sino = 1-2 sinto Ť 2 sino + sino -1=0 for Quadratic equalion ax² + bxte=0 x= -b ± √b²-4ac 2.a here x=sino a=2 b=1 c=-1 ... Sino a 17/12_4(2)(-1) 2 (2) -19 4

option & 14.99€ +oEC)'(098+, 251'(0,09€ +20€)-02 h is an integer. where (ULC+05) Cullet06-) = 0 (4.6+,051) (016+0€) = 0 OEG (10.06- = OGI (20)0€ = 0 - (1-)1415 (5.0), 415 QUIS Sino = 0.5 ; 0.5 OUIS