Question

Show full handtracing of the following code and describe what it accomplishes.

Show full handtracing of the following code and describe what it accomplishes.//The input file, dataofunknownorigin. In, contains the following data://1 2 2 4 3 6//-8 2 0 0 6 3 # include <iostream> # including <fstream> using namespace std; struct aThing {double one; double two;}; bool theseAreGreenEggsAndham (aThing, a Thing); aThing fromHorton (ifstreams); void drumingOnADrum (aThing); int main () {ifstream somewho; somewho. open ("detaofUnknownorigin.in"'); aThing thingone, thingTwo, thingThree; thingone = fromHorton (somewho); while (! Somewho. eof ()) {thingTwo = fromHorton (somewho); thingThree = fromHorton (somewho); if (theseAreGreenEggsAndHam (thingone, thingTwo, thingThree)) cout << "YES:"; else cout << "No:"; drumingonADrum (thingone); cout << ", "; drummingonADrum (thingTwo); cout << ", "; drummingonADrum (thingThree); cout << "." << endl; thingone - fromHorton (somewho);} return 0;} bool theseAreGreenEggsAndHam (aThing thA, aTHing thB, aThing thC) {return (((thA.one-thc.ine)/(thA.two-thc.two)) -- ((thA.one-thB.one)/(thA.two-thB.two)));} aThing fromHorton (ifstream delta cindyLouwho) {aThing It; cindyLouwho >> thingIt.one >> thingit.two; return thinit;} void drummingonADrum (aThing oneThumb) {cout << "(" << oneThumb.one << "." << oneThumb.two << ")";}

Answer 1

each line of file contains 6 inpus, (3 points in 2D plane).
   1) While file is not end
   2) We are reading these 6 variable in 3 aThing struct variable.
   3) Function theseAreGreenEggsAndHam checks if these three points are collinear, that is
       if slope of (A, C) is same as slope of (A, B)
       so, if (A.one - C.one) / (A.two - C.two) == (A.one - B.one) / (A.two - B.two)) return true;
            else return false.
       for the 1st input A(1, 2), B(2, 4), C(3, 6)
           (A.one - C.one) / (A.two - C.two) = (1 - 3) / (2 - 6) = 2 / 4 = 1 / 2
           (A.one - C.one) / (A.two - C.two) = (1 - 2) / (2 - 4) = 1 / 2
           equal so, it returns false,
       for the 2nd input A(-8, 2), B(0, 0), C(6, 3)
           (A.one - C.one) / (A.two - C.two) = (-8 - 6) / (2 - 3) = -14 / -1 = 14 / 1
           (A.one - C.one) / (A.two - C.two) = (-8 - 0) / (2 - 0) = -8/ 2 = -4 / 1
           not equal, so it returns false
   4) Print yes if lines are collinear, along with points
       Print no if lines are not collinear, along with points

   output:

   sanjiv@sanjiv-VirtualBox:~$ g++ file1.cpp -o file1
   sanjiv@sanjiv-VirtualBox:~$
   sanjiv@sanjiv-VirtualBox:~$ ./file1
   YES :1 2,2 4,3 6.
   NO :-8 2,0 0,6 3.