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A 0.882 g sample of an unknown gas in a 531-mL container generates a pressure of...

A 0.882 g sample of an unknown gas in a 531-mL container generates a pressure of 103.0 kPa at 298 K. What is the molecular mass of the gas?

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We will sowe this Heuring the Ideal gas - AVE MRT question equation P = 103.0 kPa R=0:0821 Lam Kel moe LV = 53 me - 531-0.531m- Ginen mass Molecular Maus 0.022 - 0.882 a molecular mass Molecular mass= 0.882 00022 =40.09 almol

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