Two forces parallel to the x axis do 19.0 J of work on a small tray...
Two forces parallel to the x axis do 19.0 J of work on a small tray while moving it 17.6 m in the x direction across a gym floor. One of the forces has a value of +3.80 N in the x direction. What is the other force?
Homework Answers
Work = Force * Distance
Work = (F2-F1) * Distance
19 = (F2+3.8) * 17.6
F2 = - 2.72 N(opp direction)
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