Question

MAKE SURE TO INCLUDE WHAT PORTION OF THE CODE GOES IN WHAT FILE FOR THE CLASS. AND A PARAGRAPH DESCRIPTION OF THE CODE AND HOW IT WORKS!!! Please include all the steps and ill give you a great rating! An array can be used to store large integersone digit at a time. For example, the integer 1234 could be stored in the array a by settinga0 t, a1] to 2, a[2] to 3, and a[3] to 4. How-ever, for this project, you might find it easier to storethe digits backward, that is, place 4 in a[0], place 3ina], place 2 in a[2], and place in a[3] QUESTION: Design, implement, and test a class in whicheach object is a large integer with each digit storedin a separate element of an array. You'll also need a private member variable to keep track of the sign of the integer (perhaps a boolean variable). The num- ber of digits may grow as the program runs, so theclass must use a dynamic array.Discuss and implement other appropriate opera-tors for this clas STEPS: A class that stores numbers in a dynamic array (so 123 would really be either arr[0] = 1, arr[1] = 2, arr[2] = 3 or arr[0] = 3, arr[1]-2, arr[2] = 1 depending on if you go forwards or backwards) You should be able to initialize the class using a default constructor (no parameters) AND by giving a number (a non-default constructor) You should be able to append digits (e.g. if the

Answer 1

package learning;

public class LargeInt {

int array[];
boolean sign;
int size;

LargeInt(){
  array = new int[5]; // Initial Size set to 5
  sign = true;     // true means positive and false means negative
}

LargeInt(int num){
  
  setNumber(num);
}

/****
*
* This function takes the number which need to be stored . Set the sign . true means positive ,false means negative.
* Count the nuber of digits in the input number. Makes the Size of the array which can store those digits. and stores the number in the array
* in forward direction.
* @param num
*/

public void setNumber(int num){
  if(num < 0){
   sign = false;
  }else{
   sign = true;
  }
  int count = countDigits(num);
  size = count;
  System.out.println("count " + count);
  while(array.length < count){
   array = increaseArraySize(array);
  }
  
  
  while(num != 0){
   System.out.println(num%10);
   array[count-1] = num %10;
   num = num /10;
   count = count -1;
  }
}

/****
* THis function is used to count the digits in the number
* @param num
* @return
*/

public int countDigits(int num){
  int count = 0;
  while(num != 0){
   num = num/10;
   count++;
  }
  return count;
}

/****
* This function dynamically doubles the array Size
* @param arr
* @return
*/

public int [] increaseArraySize(int [] arr){
  int [] brr = new int[(arr.length *2)];
  for(int i=0; i<arr.length; i++){
   brr[i] = arr[i];
  }
  return brr;
}

public String toString(){
  StringBuilder sb = new StringBuilder();
  if(sign){
   sb.append("+ ");
  }else{
   sb.append("- ");
  }
  for( int i =0 ; i<size; i++){
   sb.append(array[i]);
  }
  return sb.toString();
}

public static void main(String args[]){
  LargeInt largeInt = new LargeInt();
  largeInt.setNumber(123456789);
  System.out.println(largeInt);
}
}