Using the values, cos(1.10000) = 0.453598 and cos(1.30000) = 0.267502, find an approximate value of cos(1.25000) using Lagrange Interpolation.
The recipe for Lagrange Interpolation to fit an nth order polynomial to n+1 data points is:

Using the values, cos(1.10000) = 0.453598 and cos(1.30000) = 0.267502
a) Find False Position function for this data.
b) Find the third-order interpolation function with Lagrange
method
c) Find the third-order interpolation function with Newton's
Divided Difference Method.
d)Find the natural spline interpolation function for the same
data
e)Draw the given points in a row using the False Position
function, the third order polynomial obtained by Lagrange and
Newton's Divided Difference Method, and the natural spline
interpolation function using MATLAB.
4-0 2
4. For the following table, answer the questions.
(1) Find the cubic Newton’s interpolating polynomial using the
first four data points and estimate the function value at x=2.5
with the interpolating polynomial.
(2) Find the quartic Newton’s interpolating polynomial using the
five data points and estimate the function value at x=2.5 with the
interpolating polynomial.
(3) Find the bases functions of Lagrange interpolation, Li(x)
(i=1,2,…,5), and estimate the function value at x=2.5 with the
Lagrange interpolating polynomial.
3 5 1...
I'm not allowed to use polyfit or polyval functions.
The hint the homework gives is setting up a linear system for
the polynomial coefficients and solving it.
The test case x = [1,2,3,4]
y = [5,-2,3,0]
x_dot = [1.5,2.5]
should result in
y_dot = -1.2500 0.2500
p = -3.333 26.0000 -61.6667 44.0000
Thanks to anyone who can answer this within the next day or
so!
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