Question

Your answer is partially correct. Try again. The drawings show three charges that have the same magnitude but may have different signs. In all cases the distance d between the charges is the same. The magnitude of the charges is 191=8.7 uc, and the distance between them is d=3.1 mm. Determine the magnitude of the net force on charge 2 for each of the three drawings. -9-d-+--+ 3 +---+---+ 1 2 3 +--- 21 Id + 4.6E4 (a) F= TN 10 N (b) F 5.21E4 (C) F = N

Answer 1

(aiq - 8.7 rec - 8.7 x 10c = 2.1 mm 3.1 X10 = 0.0031.m +9 and a ta Tnet - Felt ta F4 F.2b = Force on charge Force on charge 25,5 2 doe to charge due to charge ③ » Ko 9x10² Nom E k19,119,1 9x10 x 2.7x10x8.1X105 (0.0031) 0.68121 3.61x106 > F - Foses.5359 N = 7.08 x10' N - Klvallal 0.68121 9X10 X 8.7 X10 X 8.7 x 10 (0.0031) 9.61×106 a = 70885.52.59 N 7.08 %104 w & Free - F + F2 = (7.08 x 107 + 7.08 x 10 ) = 141771.07 N. fonet - 14.17 x not w Foet = - F + -> Foet = 7.08 x 10'N - 7.08 x10' N - ON +0) + Fnet =ON > 0 Frer = ON Fret - ( 1² + (5223 - 1 (7.08 107 3² + (7.02 x 103² Fonet - 12 x 7.8 x 107 er 3 Fonet = 400 126.32 N = 10.01 x 10 n - Pret - 10.01 x 107 ) tik te Friet y123