Question

H(=) H(E) H-(-) | [7] الريال T 7) پز xb

Topic: Realisation of Digital Filters

A filter has the following realisation: where the values of the multipliers are a1=-0.57, a2=-0.56, b1=0.55 and b2=0.69.

Answer the following, giving answers to four decimal places.

PART 1

For the following transfer functions:

H1(z) = (z+γ1)/ (z+γ2)

and

H2(z) = (z+γ3)/ (z+γ4)

determine the values of the coefficients:

γ1=_____

γ2=_____

γ3=_____

y4=_____

Answer 1

SO14! rin) M1121 U212) Yin) feedback [feedbar A bi bz 92=-0.56 ar=-0.57, bis 0.55, b2=0.69 heft sice, arrow forme feedback Rembera going in love term it means it has negative if Coefficient will be positie it means -Yin) win) T -0-57 0.55 -0.56 0.69 2 +0.55 2 +0-61 H, (2) = and 12(2) = 2 +0:57 2+0.56 ::4, 50.55 42=0.57 43 = 0.69 Y = 0.56

It is a cascade form of realization, in which two filter are cascaded one after another.

Where H1(z)=Z+0.55/z+0.57

And H2(z)= z+0.69/z+0.56

Note-please find me in comment box if you find any difficulty. It is cascade realization of filter, hence it is divided into two filter H1(z) and H2(z). Please let me know if you want more information. Good luck