Question

37. .. A golfer gives a ball a maximum initial speed of 34.4 m/s. (a) What is the longest possible hole-in-one for this golfer? Ne- glect any distance the ball might roll on the green and assume that the tee and the green are at the same level. (b) What is the minimum speed of the ball during this hole-in-one shot? 38... What is the highest tree the ball in the previous problem could clear on its way to the longest possible hole-in-one? 39. The "hang time" of a punt is measured to be 4.50 s. If the ball was kicked at an angle of 63.0° above the horizontal and was caught at the same level from which it was kicked, what was its initial speed?

37,38, & 39

Answer 1

37) a) the Velocity is given 34.4m/s , g = accleration due to gravity is 9.8 m/s2

The longest possible hole in one shot is range of projectile motion

vasin 20 R =

here for max value R =
R=
,   
ford = 45

so , R = 34.4*34.4 / 9.8 = 120.75 m  

b) The minimum speed is at the highest point there y component of velocity is 0 and thus velocity has only x component

V min = v.cosé

for   

0 = 45°cost =

Vmin = 34.4 F = 24.33m/s

38 . The highest tree should be upto the max height H =

v sine H= 1 29

putting the above used values ,we have  H = 30.18 m

39. For  hang time t = 4.5s and angle 63 degree , the velocity V is

the hang time is time of flight T ,

2v.sino T =-

putting the values  T= 4.5 s , sin 63 = 0.891 , g = 9.8 m/s2

V = 24.75 m/s