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ind the area of the shaded region under the standard distri z =-0.90-t t z 1.60 2.5000 0.7611 0.9452 0.1841
2. Find the z score that corresponds to Po9, the 99th per curve O2.33 0.01 0.99 2.33 3. Following a standard normal distribut
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Answer #1

Solution

Q1

The area of the shaded region

= P(Z < 1.6) – P(Z < - 0.9)

= 0.9452 – 0.1841

[referring Standard Normal Tables or Using Excel Function: Statistical NORMSDIST]

= 0.7611 Second Option Answer

Q2

If t is the Z-score corresponding to P99, then by definition, P(Z < t) = 0.99

=> t = 2.3263 [referring Standard Normal Tables or Using Excel Function: Statistical NORMSINV]

First Option Answer

Q3

Unable to provide answer because the image is cropped at the right. Answer

DONE

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