I have the correct answers but don't know how to solve these correctly?
|
The naturally occurring charge on the ground on a fine day out in the open country is 2.59 nC. What is the electric potential at a height of 3.83 m? |
|||||||||||||||
In open heart surgery, a much smaller amount of energy will defibrillate the heart. Heart defibrillators store 35 J of energy and the voltage is applied to a 7 μFcapacitor. Find the amount of stored charge. Give answer in terms of mC.
|
|||||||||||||||

I have the correct answers but don't know how to solve these correctly? The naturally occurring...
PLEASE HELP AND EXPLAIN e.In open heart surgery, a much smaller amount of energy will defibrillate the heart. Heart defibrillators store 38 J of energy and the voltage is applied to a 7.3 μFcapacitor. Find the amount of stored charge. Give answer in terms of mC. d.An electrostatic paint sprayer has a potential of 25.0 kV that repels paint droplets onto a grounded object. What charge must a 0.8 mg drop of paint have to arrive at the object with...
-1 16 19.4 P044 0/20 Submissions Used The naturally occurring charge on the ground on a fine day out in the open country lis -1.00 nC/m2 (a) What is the electric held (in N/C) relative to ground at a height of 7.20 m? (Indicate the direction with the sign of your answer. Assume that the pesitive direction is up.) N/C (b) Calculate the electric potential (in V) at this height Sketch electric field and equipotential lines for this scenario. (Submit...
I need correct answers. If you do not know how to solve it
please do not answer, or copy other similar answers. I will rate
the correct answer.
A parallel plate capacitor of capacitance Co has plates of area A with separation d between them. When it is connected to a battery of voltage Vo it has charge of magnitude Oo on its plat It is then disconnected from the battery and the space between the plates is filled with...
I don't know why the answer is
wrong, I got K(final) = 1.1072x10^-15 J and K(initial) =
1.4576x10^-15J, with the work energy theorm I got q=(Kf-Ki)/(Vi-Vf)
= +5.48x10^-18 C
Your answer is partially correct. Try again. A moving particle encounters an external electric field that decreases its kinetic energy from 9100 eV to 6990 eV as the particle moves from position A to position B. The electric potential at A is-41.0 V, and that at B is +23.0 V. Determine...
I have already solved for the correct answers on #1,and #2; however, I have not been able to get answers for #3,#4, and #5. A solid insulating sphere of radius a = 4 cm is fixed at the origin of a co-ordinate system as shown. The sphere is uniformly charged with a charge density ρ = -114 μC/m3. Concentric with the sphere is an uncharged spherical conducting shell of inner radius b = 12.9 cm, and outer radius c =...
T/F
Correct Answers?
8. A-cnohvoitae F2uC charge moves between two positions in an electric fie instead, it ld. If it had been +would double. the same voltage, but the system's potential energy change 9. Four point charges amount of charge then the electric potential and electric field at the center is zero. are placed at the corners of a square as shown. If they all have the same ge...+o 10. The voltage between the plates of a charged capacitor is...
Hi I just need to know if these statements are true or false and why!! 1. Electric field lines always point from higher to lower potential, meaning that a positive test charge would then seem to "fall" in the correct direction. 2. A student measures the potential between parallel plates A and B, and the meter reading is +30 V. The student concludes that there is a charge on plate B, but none on plate A. 3. If a capacitor...
(7%) Problem 5: Suppose you have the 7.75 F capacitor of a heart defibrillator at a potential difference of 17.5 x 104 V. Randomized Variables V-17.5 x 104 v 50% Part (a) What is the energy stored in it in J? U 118671.88 U-118700 Correct! | 50% Part (b) Find the amount of stored charge in mC. Grade Summary Deductions 0% Potential Q = 13.561 100% (7%) Problem 15: select part Charges move in an electric field due to the...
Calculation: Neatly solve the question in the space provided. Demonstrate all important steps and include units. Your final answer must be written in the box to be considered correct. 1 point each. 6) A 2nC point charge and electric field form a system. If the charge moves through a potential difference of +10 V, what is the potential energy change of the system? Answer: 7) The average field between two points is 100 N/C. If the points are that are...
please I want only the answer without the solution and
correct answer
QUESTION 12 The formula for the change in electric potential energy for a charge moving between charged parallel plates is U = Ed or U = kQq/ U = Ed v=kQ/ U =kQqr