Question

Problem: 3 kN/m The beam is supported by the roller at A and a pin at B. Find the reactions at A and B. 30° 3 m 4 m

Answer 1

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Equations of Equilibrium N_A can be determined directly by writing the moment equation of equilibrium about point B by referring to the FDB of the beam shown in Figure + Sigma M_B = 0: 3(4) (2) - N_A sin 30 degree (3 sin 30 degree) - N_A cos 30 degree (3 cos 30 degree + 4) = 0 N_A = 3.713 kN = 3.71 kN using this result to write the force equation of equilibrium along the x and y axes, rightarrow^+ Sigma F_x = 0: 3.713 sin 30 degree - B_x = 0 B_x = 1.856 kN = 1.86 kN + uparrow Sigma F_y = 0: B_y + 3.713 cos 30 degree - 3 (4) = 0 B_y = 8.7846 kN = 8.78 kN