Question

DETERMINE THE FRICTION FORCE BETWEEN THE Book SND THE ROUGH FLOOR. PREPORE 1 UNIFORon THE REQUIRED PRO'S. 700 N E 20° 70.9 To.sm UN mach=100kg F.H.N 1.6m * 0.33 Mica 0.21 b) Hock iP THE mock tipsovER.

Answer 1

o SIM FTON 1 20 700 casio fg = MSN m = Vook N+ rousinzo = mg N = 400x10 - 100 x 0.342. yooo - 139.414 N = I N= 3760N f = US N= 0.334 3760 I fs = 10un O-SM- Y6M ---→ Fy = 700 sinzo = 299.4IUN N= mg = Fx = 37600 4oooN 657.789 for block tips over mg xo-8 < NXO.B + F xx oog 4000 x018< 37001o.B + 65176 y og 3200 < 3008 + 532.002. 3200 < 300 v so black will tipe oven

Answer 2

solution 700 N 1250 us = 0.33 up = 0.21 o free boc will be as follown 700 Now let vertical force =0 as for equilibrium 5) N + 700 Sin 20° » N = mg - 700 sin20° - 10ugxg. 81- 700 sinzo = : 99 0530sessup 741.585 N

now static friction = MN = 0.33 X 741.5858 = 244.723 N & Horizontal component of force - 700 X COS 20° = 657.784 N force is greater Here horizontal component of than static friction force Body is moving » Kinetic friction will act on this = fx = uxx M 1 0.29 x 741.5858 = 215.05988 Ni

M 1 700 sinzo 1 2700 a 700 cos 20° Now mg (Point o z for Block to topple torque of ng should be less than torque din 700 cuszoo about point o » Mow torque of mg 100 X 9.81 x 16 M 2 784.8 mm Now torque of 700 cos2o M force = 700x cos2ox = 296.021 Nm. - torque of mg > torque of 700 cosso N * Block will not tip-over or topple.