Question

What total gas volume (in litres) at 520 degrees Celsius and 1.16 ATM is produced from the decomposition of 34g of potassium bicarbonate according to the balanced equation : 2 KHCO3 = K2CO3 (s) + CO2 (g) + H20 (g) ?

Answer 1

the decomposition

KHCO₃ (s)  = K₂CO₃ (s) + CO₂ (g) + H₂O (g)

2 MOLES OF POTASSIUM BICARBONATE IS DECOMPOSED TO GIVE I MOLE OF CARBON DIOXIDE GAS AND 1 MOLE OF WATER VAPOUR. AT 120 DEGREES CENTIGRADE.

MOL WT OF POTASSIUM BICARBONATE IS 98

THEN 34 GRAMS BECOMES 0.346 M

0.346 M OF POTASSIUM BICARBONATE YIELDS 0.173 M OF CARBON DIOXIDE GAS AND 0.173 M OF WATER VAPOUR.

SIMILARLY, AT 520⁰ C TEMPERATURE AND AT 1.16 atm PRESSURE, THE YIELDS ARE 0.311 M OF CARBON DIOXIDE GAS AND 0.311 M OF WATER VAPOUR.

WHEN CONVERTED, IT COMES TO 0.070 L OF CO₂ AND 0.030 L OF H₂ O

THUS A TOTAL OF 0.100 L OF GAS IS PRODUCED.