18) molar mass of (CH3)2CO:
=2 (molar mass of C) + 1 (molar mass of oxygen) + 6 (molar mass of hydrogen)
= 3(12.0107) + 1 (16.00) + 6 (1.00794)
= 36.0 + 16.0 + 6.05 = 58 g
Therefore, the molar mass of (CH3)2CO = 58 g
option A is correct
19) molar mass of KMnO4 = 158.034 g/mol
percentage by mass of oxygen = (mass of oxygen / moalr mass of KMnO4)*100
percentage by mass of oxygen = (64 / 158.034)*100 = 40.5 %
Therefore, option C is correct
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