The vapor pressure of solid iodine is: p.7.632 Torr @ T-68.8 ℃ P-615.7 Torr @ T-154.3...

Question

Question

The vapor pressure of solid iodine is: p.7.632 Torr @ T-68.8 ℃ P-615.7 Torr @ T-154.3 ℃ Determine Δ for 12(s).

science chemistry

Answer 1

Answer #1

P1 = 7.732 torr T1 = 68.8+273 = 341.8K

P2 = 615.7 torr T2 = 154.3+273 = 427.3K

logP2/P1 = $\Delta$ H/2.303R [1/T1 -1/T2]

log615.7/7.732 = $\Delta$ H/2.303*8.314 [1/341.8-1/427.3]

1.9010 = $\Delta$ H(0.00292-0.00234)/19.147

1.9010 = $\Delta$ H*0.00058/19.147

$\Delta$ H = 1.9010*19.147/0.00058 = 62755.943J = 62.756KJ >>>>>answer

Answer 2

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