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a Amazon High Volu... Transfer Students .. Final Grade Calculat... Transcript Ordering... Transfer Admissio... Columbia Universit... MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION 4 BACIC hapter 11, Problem 052 GO Incorrect cockroach of mass m lies on the rim of a uniform disk of mass 6.00 m that can rotate freely about its center like a merry-go-round. Initially the cockroach and disk rot ogether with an angular velocity of 0.219 rad/s. Then the cockroach walks halfway to the center of the disk. a) What then is the angular velocity of the cockroach-disk system? b) What is the ratio K/Ko 0f the new kinetic energy of the system to its initial kinetic energy? 00027 This answer has no units 6.376 m ) K/Ko Open Show Work lick if you would like to Show Work for this question: SHOW HINT GO TUTORIAL VIDEO MINI-LECTURE LINK TO SAMPLE PROBLEM TO SAMPLE PROBLEM

Answer 1

The Initial angular momentum of the dyk is Lo I wo I = /2 m₂ R² L0 = Womy R² The Lic= mvir angula velocity of V =Rwo the disk Lic = m, wo R² The coral angulas momentum is the sum of the angulas monelta of the disk and the cockroach ti wo mz R & m, wor? 14- mpwa (h) + 2 mz wp p? Then the is conserved angulas momentum 4=li we ( 4 m, R² + 1 M R) = Wo (m. R² + m2 R²) -[m, R²+ m₂ R²/ 7 I m, R²u+ m₂ R²/ 20o. (it (matm, )/2 (4 + (malm, )/2 - 1.33 (0.219) = (0.291 rad /s)

energy is 6 the initial K kinetic I w? the final kh Lw and initial knetic energies all. К: 54 , Ко - Liwa K - LfW412 Ro Twil2