







2. a. The F is more electronegative than the Xe so that, 4 dipoles are formed. These dipoles can cancel each other so that, the molecule is nonpolar. The nonpolar molecules are united by dispersion forces.
The N is more electronegative than the I. The N can attract electrons to itself so that, one dipole is formed so that, the molecule is polar. The polar molecules are united by dipole-dipole forces. Also, the N that is a very electronegative atom is united to
hydrogen atoms so that, this molecule can also form hydrogen bonds. The hydrogen bonds are stronger than the dipole-dipole forces. C. Ct e l cl 서- The Cl is more electronegative than the C so that, 2 dipoles are formed. These dipoles cannot cancel each other so that, the molecule is polar. The polar molecules are united by dipole dipole forces.
d. CsCl2 The Cs is a metal while the Cl is a nonmetal. The Cs gives electrons to the Cl to form ionic bonds. 2. a. The C (diamante) is a covalent solid because the atoms are contained in networks. b. The Co is a metallic solid because it is formed for metallic atoms c. The ClBx is a molecular solid because it is formed for molecules that are united by covalent bond. d. The CaCl2 is an ionic solid because it is formed by ions
T2 Ti PF vapor pressure at T2= 400.0 torr Pi= vapor pressure at T1= 10.0 torr AH vaporization enthalpy vap R- ideal gas contat 8.314x 103 kJK mol T2- temperature 2-150.6°C+273-423.6 K T1= temperature l=55.7°C+ 273-328.7 K 4 3 2
400.0 tor 110.0 torr ΔΗ. vap Ln 8.314 x 10- K mol 423.6 K 328.7 K vap RT K mol (-6.82 x 10-4 8.314 x 10-3 / vap 8.314 x 10-3/ k χ (6.82x 10-4 K mol mol kJ Ln40 0.0820 -ΔΗνα p Ln40 0.08202 ΔΗνο 0.0820mol 44.99--= ΔΗ mol
vap T2 T1 P2= vapor pressure at T2 Pi= vapor pressure at T1= 10.0 torr AHyap vaporization enthalpy 44.99 kJ/mol R= ideal gas constant= 8.314 x 10-3 kJ/K mol T2= temperature 2=90°C+ 273-363 K TI-temperature 1 55.7°C + 273 328.7 K kI Ln10.Otorr =8.3144199그 100torr = 44409 -x(363K-3281R) x(-287 x 10-1 10.0 torr 8.314 x 10 K mo mo 363 K 328.7 K kI 10.0 torr 8.314 x 10 K mol
P2 10.0 torr Ln = 1.56 10.0 torr P, = 10.0 torr xe 1.56 2 47.59 torr