Question

I need help solving for these two problems! Thank you!

What is the magnitude of the electric field 20 cm away from a 100 nC charge? Show your calculation. What is the electric potential 20 cm away from a 100 nC charge? Show your calculation.

Answer 1

The electric field can be found out using the formula

$E = \frac{1}{4\pi\epsilon_0}\frac{q}{r^2} = 9 \times 10^9 \times \frac{100 \times 10^{-9}}{(20 \times 10^{-2})^2} = 22500N/C$

The potential is given by the formula

$V = \frac{1}{4\pi\epsilon_0}\frac{q}{r} = 9 \times 10^9 \times \frac{100 \times 10^{-9}}{20 \times 10^{-2}} = 4500V$

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