
7. What is the Ecell of a cell that has 0.40 M Al3+ Solution and 1,25...
A voltaic cell consists of an Al/Al3+ half-cell and an Fe2+/Fe3+ half-cell. Calculate Ecell when conc. of Fe2+= 0.402 M, Fe3+= 0.073 M and Al3+= 0.239 M. Use the reduction potentials for Al3+ is -1.66 V and for Fe3+ is 0.77 V. How do you decide which is oxi, red.
Consider the voltaic cell and reduction half potentials: Zn(s) | Zn 2+(aq) (0.100 M) || Ni2+(aq) (1.50 M) | Ni(s) Zn 2+ (aq)/Zn (s) E o = - 0.760 V Ni2+ (aq)/Ni (s) E o = - 0.230 V a) Sketch the voltaic cell represented with the above line notation. Label the anode and cathode and indicate the half-reactions occurring at each electrode and the species present in each solution. Also indicate the direction of electron flow (3 marks). b)...
Consider a galvanic cell that contains a Zn metal electrode and a 0.10 M Zn(NO3)2 solution in one half-cell and a Sn metal electrode and a 0.10 M Sn(NO3)2 solution in the other half-cell. If the measured Ecell value is +0.60 V and the Zn2+/Zn reduction potential is assumed to be -0.79 V, what is the Sn2+/Sn reduction potential? Show all work
A voltaic cell represented by the following cell diagram has Ecell= 1.409 V . Zn(s)|Zn2+(1.00M)||Ag+(saturated Ag2X)|Ag(s) What must be the Ksp of Ag2X? Use the following standard electrode potentials: Zn2+(aq) + 2e- →Zn(s) E° = -0.764 V Ag+(aq) + e- →Ag(s) E° = 0.799 V To enter your answer, multiply your Ksp by 1x109 then enter it to 2 decimal places.
Mcasured Cell Potentials of Redo x Couples from cells A1. A2, Bl. B2, and Unknown #1 Redox Measured Anode Anode Reaction Cathode Cathode Reaction CouplePotential Cu-Zn 10.qqv|Zn |2n→ (Al-B2) Cu-Pb Pb-Zn (BI-B2) 0-46V Fe-Pb Fe-Zn Cu-Fe (AI-A2) Zn-Unk#1 (B2-A3) 0.3Iv Unkel Assuming that the reduction potential for Zn2 (0.10 M/Zn is equal to -0.79 V, calculate the reduction potentials for the remaining cells: Cu (0.10 M/Cu 0.2ov Calculation: 95 0- 0.71-0.20V zn ls) 2 ทั้า(o.1o)11 Fe2+Co.10m) 1 Fecz) Fe (0.10...
Calculate the cell potential for the reaction as written at 25.00°C, given that [Zn2+] = 0.758 M and [Fe2+] = 0.0140 M. Use the standard reduction potentials in this table. Zn(s) + Fe2+ (aq) = Zn²+ (aq) + Fe(s) Zn2+(aq) + 2e- → Zn(s) -0.76 Fe2+(aq) + 2e- > Fe(s) -0.44
7. A is cell made by placing Zn(s) in Zn2 (aq) and Au(s) in Au (aq). Use Standard Reduction Potentials. (12 points) a. Write the half reaction for the reaction at the cathode: Calculate the voltage for the standard cell (IM Zn2* (aq) and 1 M Au?* (aq). c. Calculate the voltage for the cell after it is 999% used up. Assume 1.00 L of each solution. (Hint: Write the overall equation.)
Mcasured Cell Potentials of Redo x Couples from cells A1. A2, Bl. B2, and Unknown #1 Redox Measured Anode Anode Reaction Cathode Cathode Reaction CouplePotential Cu-Zn 10.qqv|Zn |2n→ (Al-B2) Cu-Pb Pb-Zn (BI-B2) 0-46V Fe-Pb Fe-Zn Cu-Fe (AI-A2) Zn-Unk#1 (B2-A3) 0.3Iv Unkel Assuming that the reduction potential for Zn2 (0.10 M/Zn is equal to -0.79 V, calculate the reduction potentials for the remaining cells: Cu (0.10 M/Cu 0.2ov Calculation: 95 0- 0.71-0.20V zn ls) 2 ทั้า(o.1o)11 Fe2+Co.10m) 1 Fecz) Fe (0.10...
1. Voltage reading for Fe-Cu cell 0.60 V 2. Voltage reading for Fe-Zn cell 0.25 V 3. Voltage reading for Cu-Zn cell 0.80 V 4. Fe2+ reduction half-reaction and Esedº Ered 5. Cu2+ reduction half-reaction and Ered Ered 6. Zn2+ reduction half-reaction and Ered Ered 7. Redox reaction of Fe-Cu cell 8. Fe-Cu Ecelº Ecell = 9. Redox reaction of Fe-Zn cell 10. Fe-Zn Ecetº Ece 11. Redox reaction of Cu-Zn cell 12. Cu-Zn Eceitº Ecelº = Questions to consider...
What is the standard emf of a galvanic cell made of a Co electrode in a 1.0 M Co(NO32 solution and a Al electrode in a 1.0 M AI(NO3)3 solution at 25°C? 0 cell Standard Reduction Potentials at 25°C Half-Reaction E(V +2.87 +2.07 +1.82 O,(g) 2H (aq)2e0(g)+HO Co3+(aq) + e-_? Co2+(aq) H,02(aq) + 2H"(aq) + 2e-_ 2H20 Cu2+(aq) + 2e-? Cu(s) AgCIs) + Ag(s) + CI(a) S02-(aq) + 4H'(aq) + 2e S02(g) + 2H20 Cu2+(aq) + e-_ Cu+(aq) Sn (aq)...