Using relation
d =s*t
Where d is the distance of the rod
s is the speed
t is the time
Since distance is same
sa/sr = tr/ta
1/19 = tr/ta
ta = 19tr
Also ta - tr = 0.16s
equating both equatins
ta = 19(ta - 0.16 )
ta = 19ta - 3.04
18ta = 3.04
ta = 0.1689 s
Hence length of the rod = 345*0.1689 = 58.267 m
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