Question

Q0,0 = f(0) = 0, Q1,0 = f(3) = 225, Q2,0 = f(5) = 383, Q3,0 = $(8) = 623, 24,0 = f(13) = 993 Matlab Project 2 Write a MATLAB function (using the above data) to implement Naville's method. Use the program to find the interpolation up to Q4,4(6) and display the solution in triangular form (matrix mm).

Answer 1

Answer:

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MATLAB

%% function y = WS2_LastName_FirstInital()

clear
clc

n = 4; %number of terms-1

x = [0 3 5 8 13];
f = [0 225 383 623 993];

xx = 6; %interp point Q(6)

Q = zeros(n+1,n+1); %initialising Q with all zeros

for i=1:n+1
Q(i,i) = f(i); %Qi,i = yi
end

for j=2:n+1
  
for i=1:j-1
Q(i,j) = (((xx-x(j))*Q(i,j-1)) - ((xx-x(i))*Q(i+1,j)))/(x(i)-x(j)) ;
end

end

y = Q(1,5);

disp(Q)

0 450,0000 -90.0000 -22.5000 -12.1154 0 225,0000 462.0000 184.8000 129,3600 0 383.0000 463.0000 405.1250 1 623.0000 475.0000 0 993.0000