Question

Experts, please write neatly so that I can understand your handwriting. Thank you =)

ta 1000 2000 2a 13a t- 510 + VA N V 1c 10 + VY 712 V₂ 1b V 100 125 2b V2 + V.) No V 100 2002 2c Figure 1 For network N; V. - Zilalla +212 Iza V2 Z. 11. + Z221 Ian And for network Nb; Vizinh 11 + Z126 120 V2. = Z210 11 + Z220 221 Notice that; 11-11-16 In = I,, - Iam and that V-V.. + Vib-(z 1a + Zib) 1, +(212a + Z120) 12 V2 =V2 + V20 - (Z211 + Z210) I, + (7221 + Z22b) 12 Thus, the z parameters for the overall network are 211 212 L221 222 Zz1a + 2316 Zzza + Z226] i. Please write by using the parameters above based on figure 1 V. -10V, Output Open circuit V2-10V, Input Open Circuit 1 V2 12 Vi 14.8mA 8.52V 12.9mA 7.42V Table 1 ii. By using the table 1, find the impedance for : 211 = V 212 V 141=0 Helico 1211,=0 221 = V 1112=0 222 = 1211,50 iii. Give your comments regarding the Z-paramaters of two Two-port Networks connected in series. If the values were different, why?

Answer 1

conclusion-

from Table data: Vi = lov, output open cinquit, I, - 14.0mA d. 52 V ci Vi ZI, I + Ziz Iz V2 = Zz, I + Z22 I 2 coccii) Izio Since output is open circuits Zi= I Zu =675.67 19 14.8m ปน Z2l= Il 8.52 = 575,67 Z21- 14.8m from Table Data ! V2 = lov, Input open cin wit, II = 12.9mA V 7.42 v I=0 When Input will be open urauit, Putting I = 0 in eq is and equii) - Zi2 = Iz 7.42 Zi2 575.19 12.9m V2 Z 22 Z22 775.19 12.9m 675.67 575.19 Zu Z12 [2] - 303 Hence こ 575.67 175.13 Zzi Zzz We add Z pahaneler :. In series connected Network, of respective Netwosks I Network A za Zb 1 2 200r + ܐ ܘ ܘ ܢܐ Z. V za Via 5lor It is a standard form, its Z matrix is as- geven parameter Zc za tz i ZA = Zc Z btzc 610 510 . ZA 510 710 Toon Mut 2 Networle ß i DOO Our 22 23 It is not in standard form, converting it from Delta to star- Zb ZI Za 73 Z. Z2 Z1 Z2 z1+z2+ Z3 100X100 Za 10+10o 200 25. Za Z1 Z3 2ь - Zi+z2+z3 100X200 Zb 900 Zb sor Z2 Z3 . Zc - ZitZ 2 + Z3 10oX 202 ZC 4oo Zc - 5or - Zc Za f Zc ZB - Z bt Zc Zc 75 50 ZB 50 100 ZA + ZB N Hence 75 50 610 570 + [ 5 o ir Sie 710 Z 685 560 Z- 810 560

Z parameter calculated experimently by table are almost same as calculated using theoritical formula, the values are not exactly same because of the errors introduced due to measuring instrument, as we determine input and output impedances by using ammeter and voltmeter.

Some heat is dissipated in resistors which cause error in reading.