Question

LP. Model Maximize Subject to Z X + Y 1X + 2Y6 5X2Y520 (C) C) On the graph on right, the constraints, and have been plotted Using the point drawing tool plot the four comer points for the feasible area The optimum solution is: X r ound your response to two decimal places Ya round your response to two decimal places) Optimal solution value = round your response to decimal places Click the graph, choose a tool in the palette and follow the instructions to create your graph

Answer 1

Answer:

X = 3.50

Y = 1.25

Optimal Solution = 3.50*8 + 1.25* 6 = 35.50

Explanation:

Both constrains are less than constrains so feasible region is the quadrilateral bounded by both axis and both lines of constrain.

Four Corner points are:

P1) (4,0) - Intersection of C2 and X-axis

Profit = 4*8 + 0*6 = 32

P2) (0,3) - Intersection of C1 and Y-axis

Profit = 0*8 + 3*6 = 18

P3) (0,0)- Origin point

Profit = 0

P4) (3.50, 1.25) - Intersection of C1 & C2

Profit = 3.50*8 + 1.25*6 = 35.50

Intersection of C1 & C2

by solving both equation:

1x + 2y = 6

5x + 2y = 20

C2 -C1 :

4x = 14

X =14/4 = 3.50

Put value of X in C1

2Y = 6 - 3.50

Y = 2.50/2 = 1.25

P4: (X,Y) = (3.50,1.25)