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Section #13070 7) A random sample of 12 chickens is selected from a chicken processin amount of fat that goes with each chicken package is 5.2, 6.1, 5.1, 5.7, 5.9, 6.7,5.0, 6.5,6.2,7.0,6.4,5.3 Construct a 95% confidence interval for the average fat in each Chicken p ackage.

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Answer #1

From the given sample

Mean \bar{x} = 5.925

Sample standard deviation S = 0.669

95% confidence interval for \mu is

\bar{x} - t\alpha/2 S / sqrt(n) < \mu < \bar{x} + t\alpha/2 S / sqrt(n)

5.925 - 2.201 * 0.669 / sqrt(12) < \mu < 5.925 + 2.201 * 0.669 / sqrt(12)

5.4999 < \mu < 6.3501

95% CI for \mu is (5.4999,6.3501)

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