Question

Determine the indices of the directions shown in Figure 1.

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Material Engineering

Answer 1

Let us start by noting the head point and tail point of each direction.

Head point is the set of coordinates of the head (arrow) of the direction in the cube of unit length.

Tail point is the set of coordinates of the tail of the direction in the cube of unit length.

Given below is the detailed solution to the problem:

t for direction a Head point = oll Tail point = 101 - Head hoint - Tail froint - 0-1 = -1 1-0 1 in 0 & Direction indices of a aue 110 o [ilo ] (-ve sign is represented) by a bar on top / of the digit For direction b e Head haid = 10 Tail point = 0 4 Head paint - tail point a 1-0 on 12-14 31 - 044 & Direction indices are : 1-1 /4 - 4 -4 i (хчула у ч. = [4 4 ] I fractions/ N to remove

for direction : Head froint = 3 Tail froint - o o Head paint - tail paint = 135-1/2 10 to & Direction indices are al l De al. 66 o [iool (Multiflying by 6 to) remove fractions)

- for direction de Head frank - 180 Tail froint = 0/40 Head paint - Tail paint a 1-0 % / 1.0 Direction indices of dare : 1 or 2 12 (2 1 2] Multiplying by 2 to I ecemove fractions ,