Question

How many milliliters of an aqueous solution of 0.182 M copper(II) sulfate is needed to obtain 10.3 grams of the salt?

Answer 1

number of moles of copper sulfate = mass of copper sulfate / molar mass of copper sulfate

number of moles of copper sulfate = 10.3 g / 159.609 g.mol^- = 0.0645 mole

molarity = number of moles of solute / volume of solution in L

0.182 = 0.0645 / volume of solution in L

volume of solution in L = 0.354 L

1L = 1000 mL

0.354 L = 354.0 mL

Therefore, the volume of solution is 354.0 mL