Homework Answers
now in this part we take intial velocity, U= 1.565 m/susing
conservation of energy
frictional energy loss= change in kinetic energy of system
-u(mg) d= 0.5m(v^2-U^2)
-0.2*12*9.8*0.5= 0.5*12*(V^2-1.565^2)
v= 0.699 m/s
comment in case any doubt..goodluck
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