Question

Chapter 27, Problem 36 GO An inkjet printer uses tiny dots of red, green, and blue ink to produce an image. Assume that the dot separation on the printed page is the same for all colors. At normal viewing distances, the eye does not resolve the individual dots, regardless of color, so that the image has a normal look. The wavelengths for red, green, and blue are Ared = 660 nm, green = 550 nm, and blue = 470 nm. The diameter of the pupil through which light enters the eye is 2.0 mm. For a viewing distance of 0.7 m, what is the maximum allowable dot separation? s = The number of significant digits is set to 3; the tolerance is +/-3% Click if you would like to Show Work for this question: Open Show Work TNV TA TEYT

Answer 1

leighs criterion 1.22n = by where y is the separation - Y= 1.22LA Note that longer wavelength has larger max separation, so we have to use the shortest wavelength of 470nm. and y = 1.228 0.78 470x 10 9 = 2.0069 x 10-4 m. 0.002