Question

int a = 5, b = 4, c = -10;

      if(!(a>b++))

            System.out.println("Value of a is: " + a);

System.out.println("We are inside the if-statement!");

            System.out.println("Value of b is: " + b);

      }else if (c%2 != 0 & c < 0){ //logical error (curly brace), syntax error

            c = c / 0;

            System.out.println(“We are now in the else section and c is a negative odd number!” + c);
      }

      else

            System.out.println(“c is even?”);

      System.out.println("We are now back outside the if-statement!");

Is there any mistakes for this programming?

Answer 1

//Main.java
public class Main {
  public static void main(String [] args) {
    int a = 5, b = 4, c = -10;
    //If it has a single statement then we can write the statement without using curly brace
    //Otherwise we have to use curly brace and write those statements inside the curly braces
    if(!(a>b++)) {
      System.out.println("Value of a is: " + a);
      System.out.println("We are inside the if-statement!");
      System.out.println("Value of b is: " + b);
    }
    else if (c%2 != 0 & c < 0){ //logical error (curly brace), syntax error
      c = c / 0;
      System.out.println("We are now in the else section and c is a negative odd number!" + c);
    }
    //As it is having single statement we can write this statement without using curly brace
    else
        System.out.println("c is even?");
    System.out.println("We are now back outside the if-statement!");
  }
}

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