Question

of the choices below, which gives the order for Increasing first ionization energies? Select one: a. Li <B< Be <C<O<N b. Li <Be <B<C<O<N o c. Li < B < Be <O<C<N d. Li < Be <B<C<N<O O e. Li <B<Be <C<N<O Oo oo

Answer 1

Xig & Xtre The First ionisation energy is the energy needed to remove one mole af loosely bound outer most election from the mole af gasious atoms to produre 1 mole af gaseous ion's in tI state. It has a unit af kI/mole. Now in second Period - li - Lit [completely 15²25' 15 25° Filled is) TCompletely be * Be I filled From left to right in a period the 1st lonisation energy increase 15 25r20 as the no af protons 1525 200 increase at we from с - left to right. So the 1525728? 15 25 2p' - e + 18tas! 15²28² 19 257 - e ct - e- N filled s2s 2p3 Half 2010 - 1525204 But in B we ration where the 18” 24 20- 07 1825 283 half filled have 15252p! Genfi electron Enfign- completely fit filled as orbital exerts effect on the 2p - election, and thus 267 a strong shielding making it easier to remove. That's why in B the 1st ionisation energy fall from be and then again increased from left to right, before again droping in so from N. So the correct order to be CEN O (Please su Nent bage)

In N40 If we see the election Configuration - N 15 25 2p3 - N+(15 25 287) od 15 28 289 2 ot (15287203) The N in its elemental state has a more shte half- filled orbital state compared to o. upon 1st Where as lonisation of goes in to O- goes to a shable half. filled orbital state. Hence, J.E. LI. EN. So, the final Ordes - Li LB LBe Le CO(N.)- Answer @ Thank you!! give ratings Please