
A150-15 person attached to a bungee cord jumps off a cliff at A. The cord has...
A 90 kg student jumps off a bridge with a 8-m-long bungee cord tied to his feet. The massless bungee cord has a spring constant of 400 N/m. You can assume that the bungee cord exerts no force until it begins to stretch. How far below the bridge is the student's lowest point? How far below the bridge is the student's resting position after the oscillations have been fully damped?
5. In bungee jumping, it is obviously important to know in advance how far an elastic cord of un-stretched length L will stretch with a given weight attached to its end. In one model for this elongation, the cord is simply considered to be a weak spring with constant k and the person tied to the end of the cord is a point mass m. Air resistance and any pendulum motion of the cord mass system are ignored. Suppose a...
Problem 15.48 A 90 kg student jumps off a bridge with a 12-m-long bungee cord tied to his feet. The massless bungee cord has a spring constant of 410 N/m. You can assume that the bungee cord exerts no force until it begins to stretch. Part A How far below the bridge is the student's lowest point? Express your answer with the appropriate units. ? MÅ Value O Units [1] = Submit Previous Answers Request Answer X Incorrect; Try Again;...
An 80.0 kg bungee jumper drops from rest off a bridge that is 200.0 m above a river. As he falls, air resistance is negligible, and the unstretched bungee cord attached to him uncoils. The mass of the bungee cord is negligible. When the jumper is 50.0 m below the bridge, the bungee cord is completely uncoiled and forms a straight line. Below that point, the bungee cord acts as a spring, obeying Hooke's law as it is stretched beyond...
A bungee jumper who has a mass of 85.0 kg leaps off a very high platform. A crowd excitedly watches as the jumper free-falls, reaches the end of the bungee cord, then gets "yanked" up by the elastic cord, again and again. One observer measures the time between the low points for the jumper to be 9.30 s. Another observer realizes that simple harmonic motion can be used to describe the process because several of the subsequent bounces for the...