Calculate the lattice energy for LiF(s) given the following:
sublimation energy for Li(s) = +166 KJ/mol
delta Hf for F(g) = +77 KJ/mol
first ionization energy of Li(g) = +520 KJ/mol
electron affinity of F(g) = -328 KJ/mol
enthalpy of formation of LiF(s) = -617 KJ/mol
Calculate the lattice energy for LiF(s) given the following: sublimation energy for Li(s) = +166 KJ/mol...
Consider the following information. The lattice energy of LiCl is ΔH lattice = −834 kJ/mol. The enthalpy of sublimation of Li is ΔH sub = 159.3 kJ/mol. The first ionization energy of Li is IE 1 = 520 kJ/mol. The electron affinity of Cl is ΔH EA = -349 kJ/mol. The bond energy of Cl2 is BE = 243 kJ/mol. Determine the enthalpy of formation, ΔHf, for LiCl(s).
Given the following information, calculate the lattice energy of CaF2 The enthalpy of formation of CaF2 -1228 kJ/mol Heat of sublimation of Ca 177.8 kJ/mol Bond dissociation energy of F2 159 kJ/mol First ionization energy of Ca 589.8 kJ/mol Second ionization energy of Ca 1145.4 kJ/mol . Electron affinity of F -328 kJ/mot [ Answer : -2644 KJİ I
Using the thermodynamic quantities shown below: construct a
Born-Haber cycle for the following reaction: Li(s) + 1/2
F2(g)
LiF(s); calculate the lattice energy of LiF.
Vaporization of Li(s): +159
F2 bond enthalpy: +155
Li ionization energy: +520
F- electron affinity: +328
LiF(s) heat of formation: -616
____________________________ Sublimation of Cu: 55 kJ/mol First Ionization Energy of Cu: 840 kJ/mol Sublimation of Au: 43 kJ/mol Second Ionization Energy of Cu: 1240 kJ/mol Bond Dissociation of Cl2: 244 kJ/mol First Ionization Energy of Au: 940 kJ/mol Electron Affinity of Cl2: -349 kJ/mol Second Ionization Energy of Au: 1790 kJ/mol Lattice Energy of AuCl: -1455 kJ/mol Lattice Energy of CuCl: -997 kJ/mol Lattice Energy of AuCl2: -3055 kJ/mol Lattice Energy of CuCl2: -2008 kJ/mol Use the above data to...
Consider the following information. The lattice energy of NaCl is ΔH lattice=−788 kJ/mol The enthalpy of sublimation of Na is ΔHsub=107.5 kJ/mol The first ionization energy of Na is IE1=496 kJ/mol. The electron affinity of Cl is ΔHEA=−349 kJ/mol. The bond energy of Cl2 is BE=243 kJ/mol. Determine the enthalpy of formation, ΔHf, for NaCl(s). ΔHf= kJ/mol
Consider the following information. • The lattice energy of NaCl is AHlattice = –788 kJ/mol. • The enthalpy of sublimation of Na is AHsub = 107.5 kJ/mol. • The first ionization energy of Na is IE1 = 496 kJ/mol. • The electron affinity of Cl is AHEA = -349 kJ/mol. • The bond energy of Cl, is BE = 243 kJ/mol. Determine the enthalpy of formation, AHf, for NaCl(s). AH= kJ/mol
Consider the following information. • The lattice energy of KCl is AHlattice = -701 kJ/mol. • The enthalpy of sublimation of K is AHsub = 89.0 kJ/mol. • The first ionization energy of K is IE1 = 419 kJ/mol. • The electron affinity of Cl is AHEA = -349 kJ/mol. • The bond energy of Cl, is BE = 243 kJ/mol. Determine the enthalpy of formation, AHf, for KCl(s). AHư= kJ/mol
Calculate the lattice energy of CaBr2. The standard heat of formation of CaBr2 is -675 kJ/mol. The first ionization energy of Ca is 590 kJ/mol and its second ionization energy is 1145 kJ/mol. The heat of sublimation of Ca[Ca(s)→Ca(g)] is 178 kJ/mol. The bond energy of Br2 is 193 kJ/mol, the heat of vaporization of Br2(l) is 31 kJ/mol, and the electron affinity of Br is -325 kJ/mol.
3. Draw the Bom Haber Cycle and calculate the lattice energies for LiF, MgO, and CaC12 using the data provided in the table below. This can be done on a separate page if you are working off this template. AH (1/2 B.E.) Electon Affinity Ionization Sublimation AH EA Energy Ionic Compoud F 80 kJ/mol 328 kJ/mol Li 520 kJ/mol 155 kJ/mol LiF -594 kJ/mol 0 249.4 kJ/mol 141 kJ/mol (15) . Mg 738 kJ/mol (19) 148 kJ/mol MgO -601 kJ/mol...