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Question 8. A study of the system, 4NH3(g) + 7O2 ----------> 2N2O4(g) * 6H2O(g), was carried out. A system was prepared with [NH3]=[O2]= 3.60M as the only components intially. At equilibrium, [N2O4] is 0.600M. Calculatevthe equilibrium concentratiok of NH3.
AUIUS H2Se, HzTe, and H2S in order of increasing acid strength. 8. A study of the system, 4NH3(g) + 702(9) 2N2O4(9) + 6H2O(g)
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Answer #1

2N2O4(q) + 6H₂O(g) Initial conch Change in cone equilibrium conch ANU318) +702 3.6M . 3.6M - 4x -7x 3.6-48 3.6.7% +2x +60 +2x

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