what is the mole to mole ratio of Fe2S3(s) to Fe(s) ?
We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
7) Calculate the mass in grams of FE2S3 (iron III sulfide) that can be produced with 375 grams of Fe (iron) based on the following equation: (1.5 point) Fe2S3(s) 3S(s) 2Fe(s) Show all your calculations above, then circle your best answer d) 415.8 g Fe2S c) 623.7 g Fe2S3 b) 698 g Fe2S3 a) 207.9 g Fe2S3
In the following reaction: 2Fe(s) + 3S(s) → Fe2S3(s) How many moles of Fe2S3 are produced when 2 moles of Fe reacts with 3 moles of S? a) 0.5 moles b) 1.5 moles c) 1.0 moles b) 5.5 moles
please help. me solve this question with work to understand
45) How many milliliters of 0.200 M Fe C13 are needed to react with an excess of Li2S to produce 0.345 g of Fe2S3 if the percent yield for the reaction is 65.0%? 3 Li2S(aq) + 2 Fe C13(aq) + Fe2S3(s) + 6 Li Cl(aq) A) 6.38 mL B) 10.8 mL C) 12.8 mL D) 25.5 mL E) 75.2 mL
Based on the following reaction: 2Fe (aq) + 35-lag) - Fe2S3(5) When a solution of Fe(NO3)3 is mixed with a solution of K,S, which of the following is not correct? To a precipitate forms 3 mol of Fe(NO3)3 reacts with 2 mol of Kęs FezSz is insoluble Fe(NO3)3 is soluble
Advance Study Assignment: Reaction Stoichiometry: The Mole Ratio Concept 1. What is the molar mass of Fe(NH(SO 6 H,0? 2. What mass of Fe(NHJSOJ 6 H,o is required to prepare 50.0 mL of a 1.50 x 10 M solution? 3. What volume (mL) of 6.0 M H,SO, is required to prepare 50.0 ml. of a solution which is 0.25 M in H,SO,? How many drops is this? (Assume 1 mL.-20. drops.) 4. In the reaction between OCI and Crt in...
The metathesis reaction between iron (III) nitrate and sodium sulfide is shown below 2 Fe(NO3)3(aq) + 3 Na2S (aq) ➝ 6 NaNO3(aq) + Fe2S3(s) How many grams of solid iron (III) sulfide can be produced by the reaction of 250.0 ml of 0.400 M iron (III) nitrate solution with 350.0 ml of 0.250 M sodium sulfide solution? Determine the final concentration of each ion in solution at the end of the precipitation reaction. Na+ NO3– Fe+3 S–2
I need help with part B
Explanation:
A mole ratio is the ratio between the amounts in moles of any
two compounds involved in a chemical reaction. The mole ratio can
be determined by examining the coefficients in front of formulas in
a balanced chemical equation.
Step 1: write the balanced chemical
equation.
Sb2S3(s) + 3Fe(s)→2Sb(s) +3FeS(s)
Step 2: calculate the moles of
Sb2S3 , Fe
Moles of Fe = mass given / molar mass = ( 25 g
/...
Q4 Solution Stoichiometry 10 Points A 25.0 ml of 0.527 M sodium sulfide(aq) and 55.0 ml of 0.243 Miron (III) nitrate are mixed together. What mass of solid iron (III) sulfide can be formed? What is the limiting reagent? Show your work for full credit. 3 Na2S (aq) + 2 Fe(NO3)3 (aq) ► Fe2S3 (s) + 6 NaNO3 (aq) The limiting reagent is Enter your answer here The theoretical yield of iron sulfide is Enter your answer here Please select...
please help!!
A 25.0 ml of 0.527 M sodium sulfide(aq) and 55.0 ml of 0.243 Miron (III) nitrate are mixed together. What mass of solid iron (II) sulfide can be formed? What is the limiting reagent? Show your work for full credit. 3 Na2S (aq) + 2 Fe(NO3)3 (aq) – Fe2S3 (s) + 6 NaNO3 (aq) The limiting reagent is Enter your answer here The theoretical yield of iron sulfide is Enter your answer here