13.) What is the pH of a solution if 25.0 mL of 0.250 M HClO4 is...
13.) What is the pH of a solution if 25.0 mL of 0.250 M HClO4 is titrated with 25.0 mL of 0.475 M Ba(OH)2?
a. 2.30
b. 10.32
c. 2.73
d. 13.54
e. 7.00
Homework Answers
Ba(OH)2 + 2 HClO4 ------------> Ba(ClO4)2 + 2H2O
millimoles of HClO4 = 25 x 0.25 = 6.25
millimoles of Ba(OH)2 = 25 x 0.475 = 11.875
millimoles of OH- = 2 x 11.875 = 23.75
23.75 - 6.25 = 17.5 millimoles of OH- left
[OH-] = 17.5 / 50 = 0.35 M
pOH = - log [OH-]
pOH = - log [0.35]
pOH = 0.45
pH = 14 - 0.45
pH = 13.55
answer = option d = 13.54
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