A particle P with mass 5 kg has position vector r(r = 7.0 m) and velocity...

Question

Question

science physics

Answer 1

Answer #1

r = 7 (cos45i + sin45j) = 4.95i + 4.95j m

v = 5 ( - cos15i - sin15j) = -4.83i - 1.29j m/s

F = 8 (cos75i + sin75j) = 2.07i + 7.73j N

angular momentum =m (v x r)

= 5 [ (-4.83i - 1.29j) x ( 4.95i + 4.95j ) ]

= 5 ( - 17.5)

= -87.6 kg m^2 /s k

Z - component = - 87.6 kg m^2 / s .......Ans

torque = r x F

= (4.95i + 4.95j ) X ( 2.07i + 7.73j)

= 38.26k - 10.25k

= 28 N m ........Ans

Answer 2

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