Question

Question: . A main sequence star is observed with its spectra being carefully measured. It is observed that the wavelength at which the highest intensity of light is observed is max = 639 nm, remember that 1 nm = 10m Part 1) What is the temperature of this star? T= Part 2) Assuming that this star has an emissivity of 1 and a radius of 7.96 x 108 m. The surface area of a circle is given by 47r. What is the power output of the star? P= Part 3) If the temperature of the star was doubled, what would the wavelength at which the maximum intensity was observed be? max = nm Check

Answer 1

The answer is,

A) 4534.89 K

B) 1.9195 * 10²⁶ W

C) 319.5 nm

a giren man = 639 nm = 639 * 10 m max @ A/c To Wein's Law 10 - max x T = 2.8978x 103 mk T = 2.8978 x 103 mk 639x109 12 Noon I4534.89 k = Power : Tatu = 5.7x10@w kq P = 5.7*108 x 458² x T 4 P = 5.7810*x 41 x(7.96x103)*x (4534.89) p = 1.9195 x 1026 W P = 1.9195 * 1026 W/ - SUNDAY Imax XT = 2.8978 * 10 mk - = Tidmax), mut max), Amax) . (A max), = I > Imun = T (domne), Tomax), - x 6391m = 314.5 mm Tz T. O T2 q nm = 319.5 nm