Question

015 10.0 points no x How much energy is required to change a 35 g is ice cube from ice at -12C to steam at 113 C? ber The specific heat of ice is 2090 J/kg.° C, the specific heat of water is 4186 J/kg.°C, the specific heat of stream is 2010 J/kg. C, the red heat of fusion is 3.33 x 105 J/kg, and the heat 1s of vaporization is 2.26 × 100 J/kg. nd Answer in units of J

Answer 1

Now 35 g = 35 times 10^-3 Kg Now first -12 degree C = 261 K ice become 273 K ice the Heat required Q_1 = ms (T_2 - T_1) = 35 times 10^-3 times 2090 times (273 - 261) = 35 times 12 times 2090 times 10^-3 J = 877.8 J Now 273 K ice become water of 273 K then required Latent Heat = Q_2 = 35 times 10^-3 times 3.33 times 10^5 [Use Q_2 = mL] = 11655 J L = Latent heat of fusion Now 273 K water become 373 K water the required heat Q_3 = ms (T_2 - T_1) = 35 times 10^-3 times 4186 times 100 = 14651 J Now 373 K water become 373 K vapour then required Latent heat Q_4 = 35 times 10^-3 times 2.26 times 10^6 = 79100 J Now 373 K vapour become 386 K steam the required heat Q_5 -= 35 times 10^-3 times 2010 times (386 - 373)